Activities of teachers
Student Activities 
Content 

Question: State how to calculate, solve,... 
HD7: Similar to HD 5 HD 8: Method 1: Solve Method 2: Calculator x 2 2 x 3 Enter 2 8 x Then CALC the input results. Get result A HD 9 : Similar to HD 8 
7. Let log a b 3, log a c 2 . Calculate log a x a) x = a 3 b 2 c b) x = a 4 3 b c 3 x 2 2 x 3 8. Find the solution set 2 8 x . A. _ S 1 ;3 . B. S 1;3 . C. S 3;1 . D. S 3 . 9. Find the solution set of the equation l og x 1 log 1 x 1 1. 2 2 A. 3 13 . B. 3 . 2 C. 2 5;2 5 . D . 2 5 . 10. Solution set of inequalities: 2019 x 3 x 1 2019 x 2 x 2 3 x x 3 0 2 A. ;0 B . C . 3 D. 3 ; 11. Mr. Y saves 75 million in the bank for a term of 3 months and an interest rate of 0.59%/month. If Mr. A does not withdraw interest at all terms, then after 3 years, Mr. A will receive the amount of A. 92576000 B. 80486000 
Maybe you are interested!
 Developing computational capacity for students in teaching exercises about power functions, exponential functions and logarithmic functions in calculus 12 high school  1
 Developing computational capacity for students in teaching exercises about power functions, exponential functions and logarithmic functions in calculus 12 high school  2
 Developing computational capacity for students in teaching exponential functions, exponential functions and logarithmic functions in calculus 12 high school  10
 Developing computational capacity for students in teaching exponential functions, exponential functions and logarithmic functions in calculus 12  16
 Developing computational capacity for students in teaching exponential functions, exponential functions and logarithmic functions in calculus 12 high school  17
Activities of teachers
Student Activities 
Content 

HD 10 : In the solution region, we CALC some values that satisfy answer C H D 11 : S n A . 1 r n Interest rate 3.0.59%=1.77%. After 3 years (12 quarters), the amount collected, both principal and interest, is: 92576000 
C. 92690000 D. 90930000 

Activity 3. Discover, evaluate, explore and solve problems 

Question: Read 
HD 12: 
12. A person regularly deposits an amount of money T in the bank every month in the form of compound interest at an interest rate of 0.6% per month. Knowing that after 15 months that person will have 10 million VND. Which of the following numbers is the amount T closest to? A. 535,000 B. 635,000 C. 613,000 D. 643,000 Answer 1 0 .0 0 0 .0 0 0 T 1 0, 6 % 1 5 1 . 1 0, 6 % T 6 3 5 .0 0 0 0 , 6 % 13. Le's mother borrowed 50 million VND from the bank in installments with an interest rate of 1.15%/month for 2 years. 
subject, division 
After n months n N * 

search, search 
To be : 

solution. 
S A 1 r n 1 1 r 

n r 
Activities of teachers
Student Activities 
Content 

HD 13: The way to calculate the remaining amount after n months is exactly the same as the formula for calculating monthly bank deposits and withdrawals: 
How much does Ms. Nam have to pay each month? A. 1361313 VND B.136132 VND C. 136131 VND D. 1361312 VND Answer: 1 r n 1 S A 1 r n X . n r 5.10 7 . 1, 0115 48 .0, 0115 X 1 , 0115 4 8 1 1361312, 807 14. How many positive integer values of the parameter are there for the equation Does 16 x 2.12 x ( m 2)9 x 0 have a positive root? A. 1. B . 2 . C. 4 . D. 3 . Answer: Return the equation to: 2.9 x 2.12 x 16 x m 9x _  HD: use mode 7  Click MODE 7 to enter into the computer 2.9 x 2.12 x 16 x f ( x ) 9x _ Select Start 9 end 9 step 1 We can see that f(x) is positive in the solution region (0.2; 2.9). 
Activities of teachers
Student Activities 
Content 

HD 14: Method 1 : Who solves?  Students: divide into 2 sides .16 x . or 9x  Students solve and find 2 values of m. The result is Method 2: Explore  Teacher: If m = f(x) how do you plan to use the calculator?  Students: can find the hemorrhoidal value range of f(x)  Teacher: What is the most effective way to find the value domain? HD 15: Method 1 : Who solves?  Students divide the two sides 4 x or 9 x  Students solve for x and get 2 solutions: x = 0; x log 2 3 9 2 The result is C Method 2: Explore 
So m = 1 and m = 2. Answer B. 15. Number of solutions of the equation 2.4 x 9 x 1 11.6 x A. 0 B. 1 C . 2 D. 3 Prize Method 2: Enter MODE 7 into the computer f ( x ) 2.4 x 9 x 1 11.6 x Select Start 9 end 9 step 1 Get 2 positive f(x) regions, 1 negative f(x) region. Conclusion: There are 2 times f(x) changes sign. The result f(x) = 0 has 2 solutions. Answer C 

Activity 4. Consolidation 
Emphasize:
 Calculate and change formulas: select a, b, c, x, y... arbitrary numbers and use CALC command
 How to solve equations, inequalities and logarithms using the CALC method.
 Apply to general problems by analyzing, evaluating, synthesizing,...
IV. LEARN EXPERIENCE, SUPPLEMENT
+ Students solve equations and inequalities quickly and accurately
+ Students can calculate expressions quickly
+ Students take tests faster.
APPENDIX 5
Grade 12A14 transcript before experimental teaching
No
First and last name 
Class 
Code 
Point 

first 
Le Thi Thuy An 
12A14 
209 
5 
2 
Dinh Nguyen Phuong Anh 
12A14 
357 
7 
3 
Nguyen Thi Hong An 
12A14 
209 
7 
4 
Nguyen Thi My Duyen 
12A14 
132 
4 
5 
Tran Khanh Du 
12A14 
357 
5 
6 
Nguyen Tien Hai 
12A14 
209 
4 
7 
Tran Hoang Gia Han 
12A14 
209 
9 
8 
Tran Tu Huyen 
12A14 
485 
2 
9 
Phan Thi Cam Huong 
12A14 
209 
5 
ten 
Luc My Linh 
12A14 
209 
5 
11 
Nguyen Thi Truc Ly 
12A14 
132 
3 
twelfth 
Tran Thi Thuy My 
12A14 
132 
5 
13 
Phan Ngoc Ngan 
12A14 
209 
5 
14 
Doan Mong Nghi 
12A14 
485 
6 
15 
Quach Tieu Nguyet 
12A14 
132 
3 
16 
La Thi Huyen Nhu 
12A14 
485 
3 
17 
Nguyen Hoang Phuc 
12A14 
132 
7 
18 
Tran Cong Son 
12A14 
132 
7 
19 
Nguyen Tien Tai 
12A14 
209 
7 
20 
Lam Gia Te 
12A14 
485 
4 
21 
Nguyen Thanh Tu 
12A14 
132 
4 
22 
Ho Thanh Tuyen 
12A14 
485 
5 
23 
Quach Thi Tuyen 
12A14 
485 
6 
24
Trinh Thanh Tuyen 
12A14 
357 
3 

25 
Ngo Quy Ty 
12A14 
209 
6 
26 
Nguyen Huu Thai 
12A14 
132 
6 
27 
Tran Ngoc Thanh 
12A14 
209 
5 
28 
Du Dong Thanh 
12A14 
209 
5 
29 
Thi Hong Tham 
12A14 
132 
5 
30 
Le Minh Thuan 
12A14 
132 
5 
thirty first 
Nguyen Thi Thu Thuy 
12A14 
485 
6 
32 
Nguyen Anh Thu 
12A14 
209 
5 
33 
Vǜ Anh Thu 
12A14 
357 
3 
34 
Vǜ Anh Thu 
12A14 
485 
7 
35 
Tran Thi Kieu Trang 
12A14 
132 
5 
36 
Nguyen Thi My Tran 
12A14 
357 
8 
37 
Phan Minh Trong 
12A14 
357 
5 
38 
Ngo Thien Trung 
12A14 
485 
3 
39 
Thai Hoang Vinh 
12A14 
485 
4 
40 
Tran Duc Vinh 
12A14 
357 
6 
41 
Bui Thi Yen Vy 
12A14 
209 
7 
42 
Tran Ngoc Yen Vy 
12A14 
209 
3 
43 
Mai Ngoc Yen 
12A14 
132 
5 
44 
HuǶnh Kim Yen 
12A14 
209 
5 
45 
La Thi Hoang Yen 
12A14 
209 
6 
APPENDIX 6
Grade 12A15 transcript before control teaching
No
First and last name 
Class 
Code 
Point 

first 
Bui Thi Hoang An 
12A15 
485 
3 
2 
Nguyen Thi Tuong Duy 
12A15 
357 
5 
3 
Vo Bao Duy 
12A15 
485 
5 
4 
Truong Thanh Dong 
12A15 
357 
4 
5 
Dang Nguyen Hung 
12A15 
357 
5 
6 
Tran Nguyen Gia Hung 
12A15 
485 
4 
7 
Tran Quoc Hung 
12A15 
132 
7 
8 
Duong My Huong 
12A15 
132 
2 
9 
Le Thi Kieu 
12A15 
485 
7 
ten 
Nguyen Tran Hoang Khang 
12A15 
357 
7 
11 
To Hoang Khang 
12A15 
209 
3 
twelfth 
Ha Phuoc Khanh 
12A15 
485 
5 
13 
Mai Truc Linh 
12A15 
209 
5 
14 
Quach Tuan Loi 
12A15 
132 
6 
15 
Nguyen Thi Diem My 
12A15 
209 
3 
16 
Ly Be Ngan 
12A15 
132 
3 
17 
Danh Xuan Nghi 
12A15 
132 
4 
18 
Nguyen Ai Ngoc 
12A15 
357 
4 
19 
Nguyen Thi Bich Ngoc 
12A15 
209 
7 
20 
Truong Thi Xuan Nguyen 
12A15 
132 
7 
21 
HuǶnh Thi Dung Nhu 
12A15 
209 
7 
22 
Le Xuan Binh Phong 
12A15 
357 
5 
23 
Nguyen Thi Hanh Phuc 
12A15 
209 
6 